Answer: Metal A is 3 times faster than Metal B.
Step-by-step explanation:
Since we have given that
Time taken to oxidised metal A = [tex]2x\sqrt{3}\ seconds[/tex]
Time taken to oxidised metal B = [tex]6x\sqrt{3}[/tex] seconds
So, ratio of metal A to metal B would be
[tex]\dfrac{Metal\ A}{Metal\ B}=\dfrac{2x\sqrt{3}}{6x\sqrt{3}}=\dfrac{1}{3}[/tex]
So, Ratio of Metal A to Metal B is 1 : 3.
Hence, Metal A is 3 times faster than Metal B.