Question

A light-rail commuter train speeds up at a rate of 1.65 m/s2 and takes 19.0 s to reach its top speed. How far down the tracks does the train go to reach its top speed if starting from rest

Answer 1

Answer:

The distance covered by the train to reach its top speed is 297.82 meters.              

Explanation:

Acceleration of the train, $a=1.65\ m/s^2$

Time, t = 19 s

Initial speed of the train, u = 0

We need to find the distance covered by the train to reach its top speed. It can be calculated using second equation of motion. It is given by :

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}\times 1.65\times (19)^2$

d = 297.82 meters

So, the distance covered by the train to reach its top speed is 297.82 meters. Hence, this is the required solution.