Answer:
Step-by-step explanation:
Let x ( in months ) denotes present age of car and y ( in months ) denotes present age of tyres.
First condition:A motorcar is 3 times as old as its tires were when it was as old as the tires are now.
Equation:
[tex]x=3\left [ y-(x-y) \right ]\\x=3(2y-x)\\2x=3y\,\,...(i)[/tex]
Second Condition:When its tires are as old as the car is now, the car will be a year older than the tires are now.
Equation:
[tex]x+(x-y)=y+12\\2x-y=y+12\\x-y=6\,\,...(ii)[/tex]
From equation (i), put [tex]x=\frac{3y}{2}[/tex] in equation (ii).
[tex]x-y=6\\\frac{3y}{2}-y=6\\\frac{y}{2}=6\\y=12[/tex]
Put y = 12 in equation (ii).
[tex]x=y+6=12+6=18[/tex]
So,
present age of car = 18 months
present age of tyres = 12 months