Question

What is the area of the region in which squares ABCD and EFGH overlap? STATEMENT 1: EF bisects BC. STATEMENT 2: The distance from point C to point E is 2√2 and the distance from point C to point F is 2√2.

Answer 1

Answer:

√4

Step-by-step explanation:

Step1: Square ABCD and square EFGH overlap in such a way that EF bisect BC and EH bisect DC.

Step 2: draw a line to join point C to point E and point C to point F to produce an equilateral triangle ECF (since the distance from E to C is 2√3 and C to F is 2√2) distance from E to F will be 2√2 for equilateral triangle.

Step 3: the overlapping region will then be square of side (2√2)/2 = √2

Hence, area of the overlapping region will be area of the square (shaded in the attachment below)

√2 *√2 = 2 or √4