C is the answer.
Number observed: AaBb (25), Aabb (25), aaBb( 25), aabb (25).
Explanation:
when true-breeding aabb is crossed with the F1 AaBb, in F2 generation
the genotype ratio will be 1:1:1:1
AaBb (25), Aabb (25), aaBb( 25), aabb (25).
The resultant offspring will have 25 percent probability of the appearance of the two genes whether heterozygous dominant or recessive or homozygous recessive.