Answer:
[tex]n^3[/tex]
Step-by-step explanation:
The number of ways of choosing [tex]r[/tex] objects from [tex]n[/tex] is [tex]\binom{n}{r}=\frac{n!}{r!(n-r)!}[/tex]. Specifically, [tex]\binom{n}{1}=n[/tex].
Since there are [tex]n[/tex] sophomores, there are [tex]n[/tex] ways of picking 1 sophomore from [tex]n[/tex].
By the same reasoning, there are [tex]n[/tex] ways of picking 1 junior and [tex]n[/tex] ways of picking 1 senior.
The total number of ways of picking 1 sophomore, 1 junior and 1 senior = [tex]n\times n\times n=n^3[/tex]