Question

One supply is a 30% solution, and the other supply is a 60% solution. On one occasion, ACC needs to manufacture 50% solution of H3PO4. Which could be the amounts they use of each to make a 50% solution of H3PO4?

Answer 1

Question is incomplete , complete question is:

One supply is a 30% solution, and the other supply is a 60% solution. On one occasion, ACC needs to manufacture 50% solution of $H_3PO_4$. Which could be the amounts they use of each to make 100 grams of a 50% solution of $H_3PO_4$

Answer:

33.37 grams of 30% phosphoric acid solution and 66.67 grams of 60% phosphoric acid solution will used to make 100 grams of 50% phosphoric acid solution.

Explanation:

Let the amount of 30% phosphoric acid solution be x and 60% phosphoric acid solution be y.

Amount of 50% phosphoric acid solution to be made= 100 g

x + y = 100 g..[1]

Amount of phosphoric acid in x grams solution = 30% of x = 0.3x

Amount of phosphoric acid in y grams solution = 60% of y = 0.6y

Amount of phosphoric acid in 100 grams of 50% solution = 50% of 100 = 50 g

0.3x  +0.6y = 50 g..[2]

Solving [1] and [2] we get :

y = 66.67 g

x = 33.33 g

33.37 grams of 30% phosphoric acid solution and 66.67 grams of 60% phosphoric acid solution will used to make 100 grams of 50% phosphoric acid solution.