Respuesta :
The quadratic formula used to solve the equation [tex]5x^{2} +3x-4=0[/tex] is [tex]x=\frac{-3 \pm \sqrt{(3)^{2}-4(5)(-4)}}{2(5)}[/tex]
Explanation:
The equation is [tex]5x^{2} +3x-4=0[/tex]
The equation is of the form [tex]ax^{2} +bx+c=0[/tex]
Thus, [tex]a=5, b=3,c=-4[/tex]
To find the quadratic formula, the general formula to find the quadratic roots is [tex]x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}[/tex]
Hence, substituting the values of a,b,c in the formula, we get,
[tex]x=\frac{-3 \pm \sqrt{(3)^{2}-4(5)(-4)}}{2(5)}[/tex]
Thus, Option A is the correct answer.
The quadratic formula used to solve the equation [tex]5x^{2} +3x-4=0[/tex] is [tex]x=\frac{-3 \pm \sqrt{(3)^{2}-4(5)(-4)}}{2(5)}[/tex]