Question

Find g(4f(2)) where f(x)=1/x+1 and g(x)=x(x+1)^2

Answer 1

Answer:

$g(4f(2))=294$

Step-by-step explanation:

from

$f(x)=\frac{1}{x} +1$

$g(x)=x(x+1)^2$

then,

$f(2)=\frac{1}{2} +1$

$f(2)=\frac{3}{2}$

$4f(2)=4(\frac{3}{2} )=6$

again,

$g(4f(2))=4f(2)(4f(2)+1)^2$

but $4f(2)=6$

$g(4f(2))=6(6+1)^2=6(7)^2=6(49)$

Therefore $g(4f(2))=294$