Question

Solve the right triangle, while a= 10; find B, b and c.

Answer 1

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for β

β = 180° - (90 + 50)° = 180° - 140° = 40°

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tan50° = $\frac{opposite}{adjacent}$ = $\frac{10}{b}$

Multiply both sides by b

b × tan50° = 10 ( divide both sides by tan50° )

b = $\frac{10}{tan50}$ ≈ 8.39 ( to 2 dec. places )

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sin50° = $\frac{opposite}{hypotenuse}$ = $\frac{10}{c}$

Multiply both sides by c

c × sin50° = 10 ( divide both sides by sin50° )

c = $\frac{10}{sin50}$ ≈ 13.05 ( to 2 dec. places )

Answer 2

Answer:

<b=40        

Step-by-step explanation:

<b=180-(90+50)    - (sum of all the angles of a triangle is 180)

=180-140

<b=40