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Find the values of angles x, y,and z.
51°
60°
389
Ox=91°; y = 51°; z = 31°
x=89°; y = 91°; z=0°
x= 60°; y = 120°; z = 31°
x = 91°; y = 89°; z = 31°

Find the values of angles x yand z 51 60 389 Ox91 y 51 z 31 x89 y 91 z0 x 60 y 120 z 31 x 91 y 89 z 31 class=

Respuesta :

Answer:

The value of x, y and z are:

[tex]x=91^{0}, y = 89^{0}, z=31^{0}[/tex]

Step-by-step explanation:

Label the image as given below.

Consider the triangle ABC.

Use the property: Sum of angles of a triangle is [tex]180^{0}[/tex], to determine the value of x as follows:

[tex]51^{0} +38^{0}+x =180^{0}\\x=91^{0}[/tex]

Use the property: Sum of angles on a straight line is [tex]180^{0}[/tex], to determine the value of y as follows:

[tex]x+y=180^{0}\\91^{0} + y = 180^{0}\\y=89^{0}[/tex]

Consider the triangle ADC.

Use the property: Sum of angles of a triangle is [tex]180^{0}[/tex], to determine the value of z as follows:

[tex]60^{0} + 89^{0} + z = 180^{0}\\z = 31^{0}[/tex]

Ver imagen warylucknow

Answer:

∠x = 91°

∠y = 89°

∠z = 31°

Step-by-step explanation:

  • the sum of the interior angles of a triangle is 180°
  • the measure of third angle = the sum of the interior angles - the sum of two angles

x = 180 - (51 + 38) = 91

∠x = 91°

  • the measure of ∠x and ∠y are on the straight line and they are both equal 180°

then to find the value of y = 180 - x

y = 180 - 91 = 89

∠y = 89°

z = 180 - (60 + 89) = 31

∠z = 31°

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