Respuesta :
The volume at [tex]1.2[/tex] [tex]atm[/tex] would be as follows:
[tex]252.23 ml[/tex]
Boyle's Law
Boyle's law states that the pressure contained by an ideal gas is oppositely proportional to the volume it has a constant temperature.
Using the law of Boyle's,
[tex]P_{1} V_{1} = P_{2} V_{2}[/tex]
Given that,
The Volume contained by the gas [tex]= 460[/tex] ml
[tex]Pressure[/tex] of the gas [tex]= 500[/tex] mm Hg
Volume at [tex]1.2 atm[/tex] [tex]= ?[/tex]
[tex]P_{1} = 500 mm Hg[/tex]
[tex]V_{1} = 80 ml[/tex]
[tex]P_{2} = 1.2 atm[/tex] [tex]760/1 = 912 mm Hg[/tex]
To find,
[tex]V_{2} = ?[/tex]
by putting the values,
[tex]V_{2} = V_{1} (P_{1}/P_{2} )[/tex]
[tex]= 460 (500/912)[/tex]
[tex]= 252.23 ml[/tex]
Thus, [tex]252.23 ml[/tex] is the correct answer.
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