Question

A student experimentally determined that 23.15 mL of an exactly 0.100 N NaOH solution was required to titrate 10.00 mL of an unknown acid solution to a phenolphthalein end point. Determine the normality of the unknown acid solution.

Answer 1

Answer: The normality of unknown acid solution is 0.232 N

Explanation:

To calculate the normality of the unknown acid solution, we use the equation:

$N_1V_1=N_2V_2$

where,

$N_1\text{ and }V_1$ are the normality and volume of the unknown acid solution

$N_2\text{ and }V_2$ are the normality and volume of NaOH solution

We are given:

$N_1=?N\\V_1=10.00mL\\N_2=0.100M\\V_2=23.15mL$

Putting values in above equation, we get:

$N_1\times 10.00=0.100\times 23.15\\\\N_1=\frac{0.100\times 23.15}{10.00}=0.232N$

Hence, the normality of unknown acid solution is 0.232 N