Answer: The normality of unknown acid solution is 0.232 N
Explanation:
To calculate the normality of the unknown acid solution, we use the equation:
[tex]N_1V_1=N_2V_2[/tex]
where,
[tex]N_1\text{ and }V_1[/tex] are the normality and volume of the unknown acid solution
[tex]N_2\text{ and }V_2[/tex] are the normality and volume of NaOH solution
We are given:
[tex]N_1=?N\\V_1=10.00mL\\N_2=0.100M\\V_2=23.15mL[/tex]
Putting values in above equation, we get:
[tex]N_1\times 10.00=0.100\times 23.15\\\\N_1=\frac{0.100\times 23.15}{10.00}=0.232N[/tex]
Hence, the normality of unknown acid solution is 0.232 N