The x and y values in the given matrices are 6 and 7 respectively.
Step-by-step explanation:
Step 1; Both the given matrices are of the order 1 × 2. So to solve the values of x and y is just a matter of substitution. We substitute the values which correspond with each other i.e we substitute the values of [tex]a_{11}[/tex] which is the element at row 1 column 1 of both matrices. Similarly, the values of [tex]a_{12}[/tex] in both matrices are substituted with each other.
Step 2; The value of [tex]a_{11}[/tex] of the first matrix is 4x and the corresponding value in the second matrix is 24. So 4x will be equal to 24. Similarly, the value of [tex]a_{12}[/tex] in the second matrix is 6y and its corresponding value in the first matrix is 42. So 6y will equal 42.
4x = 24, x = [tex]\frac{24}{4}[/tex], x = 6
6y = 42, y = [tex]\frac{42}{6}[/tex], y = 7
