Question

Calculate the number of moles of sulfuric acid that is contained in 0.250 mL of 0.500 M sulfuric acid solution.

Answer 1

Answer:

0.000125 moles

Explanation:

Firstly, we need to know the meaning of the 0.5M. This simply means 0.5 moles are present in 1L or 1dm^3. 0.5M could also be written as 0.5moles/L.

Now, we know that there are 0.5 moles in 1L, we now need to calculate the number of moles in 0.5ml.

It is necessary to know that 1000ml = 1L.

Now if 0.5 moles = 1000ml

xmoles = 0.25ml

X = (0.25 * 0.5)/1000 = 0.000125 moles

Answer 2

The number of moles of the sulfuric acid in the given new volume of the acid is 1.25 x 10⁻⁴ mole.

The given parameters;

• volume of the sulfuric acid, V₁ = 0.25 ml
• concentration of the acid, C₁ = 0.5 M

The concentration of the sulfuric acid is calculated as follows;

$C_1 V_1 = C_2 V_2\\\\C_2 = \frac{C_1 V_1}{V_2} \\\\C_2 = \frac{0.5 \ M\ \times \ 0.25 \times 10^{-3}\ L}{1 \ L} \\\\C_2 = 1.25 \times 10^{-4} \ mole$

Thus, the number of moles of the sulfuric acid in the given new volume of the acid is 1.25 x 10⁻⁴ mole.

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