Question

Hydrogen chloride and oxygen react to form chlorine and water, like this:

4 HCl(g)+O2(9) ---> 2 Cl2(g)+2 H20(g)

Write the pressure equilibrium constant expression for this reaction.

Answer 1

Answer:

Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴

Explanation:

This is the reaction:

4 HCl (g) + O₂ (g)  ⇒ 2 Cl₂ (g)  + 2 H₂O(g)

Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴

Answer 2

Answer:

Kp = ((pH2O)²*(pCl2)²] /((pO2)(pHCl)^4)

Explanation:

Step 1: data given

Hydrogen chloride = HCl

oxygen = O2

chlorine = Cl2

water = H2O

Step 2: The balanced equation

4 HCl(g)+O2(g) ⇒ 2 Cl2(g)+2 H20(g)

Step 3: Define the pressure equilibrium constant

Kc = [[H2O]²*[Cl2]²] /[[O2][HCl]^4]

Kp = ((pH2O)²*(pCl2)²] /((pO2)(pHCl)^4)

⇒ with pH2O = the partial pressure of H2O

⇒ with pCl2 = the partial pressure of Cl2

⇒ with pO2 = the partial pressure of O2

⇒ with pHCl = the partial pressure of HCl