Question

Forrest is playing a four-player card game with his three grandchildren. His three grandchildren are all equally likely to win, but Forrest’s experience and cunning make him twice as likely to win as each of his grandchildren. What is Forrest’s probability of winning? Express your answer as a common fraction

Answer 1

Answer:

2/5

Explanation:

This problem can be easily solved if we consider Forrest's experience as an "extra player" since he has twice the probability of winning of any other participant. Considering Forrest (and his expertise) and all three grandchildren, the probability of winning for each grandchildren is:

$P(G)=\frac{1}{3+1+1}=\frac{1}{5}$

Since Forrest is twice as likely to win, his probability of winning is:

$P(F) = 2*P(G)=2*\frac{1}{5}=\frac{2}{5}$

Forrest’s probability of winning is 2/5.