Question

How much energy (in kilojoules) is required to convert 200 mL of diethyl ether at its boiling point from liquid to vapor if its density is 0.7138 g/mL?

Answer 1

Answer:

55.96kJ

Explanation:

Energy = mass of diethyl ether × enthalpy of vaporization of diethyl ether

Volume (v) = 200mL, density (d) = 0.7138g/mL

Mass = d × v = 0.7138 × 200 = 142.76g

Enthalpy of vaporization of diethyl ether = 29kJ/mol

MW of diethyl ether (C2H5)2O = 74g/mol

Enthalpy in kJ/g = 29kJ/mol ÷ 74g/mol = 0.392kJ/g

Energy = 142.76g × 0.392kJ/g = 55.96kJ

Answer 2

The heat energy required to convert 200 mL of diethyl ether at its boiling point from liquid to vapor is 55.85 KJ

We'll begin by calculating the mass of the diethyl ether. This can be obtained as follow:

Volume = 200 mL

Density = 0.7138 g/mL

Mass of diethyl ether =?

Mass = Density × Volume

Mass of diethyl ether = 0.7138 × 200

Mass of diethyl ether = 142.76 g

• Next, we shall determine the number of mole in 142.76 g of diethyl ether

Mass of diethyl ether = 142.76 g

Molar mass of diethyl ether = 74.12 g/mol

Mole of diethyl ether =?

Mole = mass / molar mass

Mole of diethyl ether = 142.76 / 74.12

Mole of diethyl ether = 1.926 mole

• Finally, we shall determine the heat energy required to convert 200 mL of diethyl ether at its boiling point from liquid to vapor. This can be obtained as follow:

Mole of diethyl ether (n) = 1.926 mole

Enthalpy of vaporization of diethyl ether (ΔHv) = 29 KJ/mol

Heat (Q) =?

Q = n•ΔHv

Q = 1.926 × 29

Q = 55.85 KJ

Therefore, the heat energy required to convert the diethyl ether at its boiling point from liquid to vapor is 55.85 KJ

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