Answer:
0.2298kg of Al
Explanation:
From the equation of reaction
3 moles of Al (81g) is required to mix with 3 moles of NH4ClO4 (352.5g)
Mass of Al required in the fuel mixture for every kilogram (1000g) of NH4ClO4 = 1000×81/352.5 = 229.8g = 229.8/1000 = 0.2298kg