For the given problem, V2= 0.77 liter or 770 cc.
Explanation:
The given data,
V1= 5,000 cc.
T1= 500 K.
T2 = 77K.
We have to calculate V2.
According to Charles law,
[tex]\frac{V1}{T1}= \frac{V2}{T2} .[/tex]
Before applying let us convert the cc into liter.
1 liter = 1000 cc.
⇒5000 cc= 5 liter.
Let us substitute the values in the formula,
[tex]\frac{5}{500}= \frac{V2}{77} .[/tex]
V2= [tex]\frac{(5)(77)}{500}[/tex].
V2= [tex]\frac{385}{500}[/tex].
V2= 0.77 liter.
In cc, V2= 770 cc.
