Question

you walk west for 52 m, then you walk 26.8° north of west for 44 m, and finally you walk due north for 25 m. Find the components of your final displacement (in m), from your initial to final point, along the north and west directions.

Answer 1

Answer:

Displacement component due to north direction=44.84 m

Displacement component due to west direction=-91.27 m

Step-by-step explanation:

We are given that

$\theta=26.8^{\circ}$

Let

A=-52i

B=$-44cos26.8 i+44sin26.8 j$

$B=-39.27i+19.84 j$

$C=25j$

Total displacement from initial point to final point D =A+B+C

Total displacement from initial point to final point

$D=-52i-39.27i+19.84j+25j$

$D=-91.27i+44.84 j$

Displacement component due to north direction=44.84 m

Displacement component due to west direction=-91.27 m