Question

A physics lab is demonstrating the principles of simple harmonic motion (SHM) by using a spring affixed to a horizontal support. The student is asked to find the spring constant, k . After suspending a mass of 275.0 g from the spring, the student notices the spring is displaced 45.5 cm from its previous equilibrium. With this information, calculate the spring constant. spring constant: 5.923 N / m T

Answer 1

Answer:

5.9291 N/m

Explanation:

m = Mass of object = 275 g

x = Displacement of spring = 45.5 cm

g = Acceleration due to gravity = 9.81 m/s²

k = Spring constant

As the forces in the system are conserved we have

$mg=kx\\\Rightarrow k=\dfrac{mg}{x}\\\Rightarrow k=\dfrac{0.275\times 9.81}{0.455}\\\Rightarrow k=5.9291\ N/m$

The spring constant is 5.9291 N/m