Answer: 784 J
Explanation:
The kinetic energy [tex]K[/tex] of the bowling ball is given by the following equation:
[tex]K=\frac{1}{2}mV^{2}[/tex]
Where:
[tex]m=2 kg[/tex] is the mass of the ball
[tex]V=28 \frac{m}{s}[/tex] is the velocity of the ball before hitting the ground
Then:
[tex]K=\frac{1}{2}2kg(28 \frac{m}{s})^{2}[/tex]
[tex]K=784 J[/tex] This is the kinetic energy of the bowling ball