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At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05. A bucket of 3 pieces of dark meat and 8 pieces of white meat costs 8.90. Find the cost of a piece of dark meat and the cost of a piece of white meat.

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Answer:

The cost of a piece of dark meat is $0.70 and the cost of a piece of white meat is $0.85.

Step-by-step explanation:

Given:

At Clucker's Chicken, a bucket of 4 pieces of dark meat and 5 pieces of white meat costs 7.05.

A bucket of 3 pieces of dark meat and 8 pieces of white meat costs 8.90.

Now, to find the cost of a piece of dark meat and the cost of a piece of white meat.

Let the cost of a piece of dark meat be [tex]x.[/tex]

And the cost of a piece of white meat be [tex]y.[/tex]

A bucket of 4 pieces of dark meat and 5 pieces of white meat costs $7.05.

So,

[tex]4x+5y=7.05[/tex]

[tex]4x=7.05-5y[/tex]  

[tex]x=\frac{7.05-5y}{4}[/tex]   .......(1)

Now, a bucket of 3 pieces of dark meat and 8 pieces of white meat costs $8.90.

[tex]3x+8y=8.90[/tex]

Substituting the value of [tex]x[/tex] from equation (1) we get:

[tex]3(\frac{7.05-5y}{4})+8y=8.90[/tex]

[tex]\frac{21.15-15y}{4} +8y=8.90[/tex]

[tex]\frac{21.15-15y+32y}{4} =8.90[/tex]

Multiplying both sides by 4 we get:

[tex]21.15-15y+32y=35.60[/tex]

[tex]21.15+17y=35.60[/tex]

Subtracting both sides by 21.15 we get:

[tex]17y=14.45[/tex]

Dividing both sides by 17 we get:

[tex]y=0.85[/tex]

The cost of a piece of white meat = $0.85.

Now, substituting the value of [tex]y[/tex] in equation (1) we get:

[tex]x=\frac{7.05-5y}{4}[/tex]

[tex]x=\frac{7.05-5\times 0.85}{4}[/tex]

[tex]x=\frac{7.05-4.25}{4}[/tex]

[tex]x=\frac{2.8}{4}[/tex]

[tex]x=0.70.[/tex]

The cost of a piece of dark meat = $0.70.

Therefore, the cost of a piece of dark meat is $0.70 and the cost of a piece of white meat is $0.85.

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