Answer:
384.6 m
Explanation:
The length of the runway airport should be long enough to accommodate the aircraft during its acceleration from rest to 161 km/h at rate of 2.6 m/s. We can use the following equation of motion to solve for this:
[tex]v^2 - v_0^2 = 2a\Delta s[/tex]
where v0 = 0 m/s is the initial velocity of the airplane when it start accelerating, v = 161 km/h = 161*1000*(1/60)(1/60) = 44.72 m/s is the airborn speed, a = 2.6 m/s2 is the acceleration, and [tex]\Delta s[/tex] is the distance of the runway, which we care looking for
[tex]44.72^2 - 0 = 2*2.6\Delta s[/tex]
[tex]\Delta s = 44.72^2/(2*2.6) = 384.6 m[/tex]