The area of poster is 32 square inches
Solution:
Let "a" be the length of rectangle
Let "b" be the width of rectangle
The length of Joseph’s rectangular poster is two times it’s width
Therefore,
Length = 2 times width
a = 2b --------- eqn 1
The perimeter is 24 inches
The perimeter of rectangle is given by formula:
[tex]Perimeter = 2(length+width)[/tex]
Substituting the given values we get,
[tex]24 = 2(2b + b)\\\\24 = 2(3b)\\\\\text{Divide both sides of equation by 2 }\\\\12 = 3b\\\\\text{Divide both sides of equation by 3}\\\\b = 4[/tex]
Substitute b = 4 in eqn 1
a = 2(4)
a = 8
Thus we got,
Length = 8 inches
Width = 4 inches
The area of rectangle is given by formula:
[tex]Area = length \times width\\\\Area = 8 \times 4\\\\Area = 32[/tex]
Thus area of poster is 32 square inches
