Question

Draw the major product of the reaction between 1-butanol and nah. include counterion in your answer.

Answer 1

Answer:

The major product of the reaction between 1-butanol and NaH is attached in the drawing.

Explanation:

In this reaction a strong base, such as NaH, deprotes the alcohol to obtain an alkoxide ion. It is the first step of the method to prepare ethers by means of Williamson's synthesis, where subsequently the alkoxide ion attacks a haloalkane.

Answer 2

Answer: Check explanation.

Explanation:

The reaction between 1-butanol and sodium hydride(NaH) is a very important reaction in industrial Chemistry in the Williamson Ether synthesis.

The 1-butanol is a primary alcohol, the Sodium(Na) in the sodium Hydride(NaH) is positively charged while the Hydrogen in the compound (that is, the sodium Hydride) is negatively charged. The Hydride is a very powerful base.

The reaction between 1-Butanol and sodium Hydride happens through the deprotonation of alcohol (1-butanol) by the sodium hydrides to give a sodium alkoxide and the evolution of Hydrogen gas.

The equation of reaction is given below:

C4H9OH + NaH ----------> CH3CH2CH2CH2 O^- Na^+ + H2.

NB: check attached file for the drawing.