Consider a hypothetical metal that has a density of 7.45 g/cm3, an atomic weight of 87.09 g/mol, and an atomic radius of 0.123 nm. Compute the atomic packing factor if the unit cell has tetragonal symmetry, values for the a and c lattice parameters are 0.471 and 0.350, respectively

Respuesta :

Explanation:

Formula to calculate the atomic packing factor is as follows.

    APF = [tex]\frac{\text{volume of sphere}}{\text{volume of unit cell}}[/tex]

            = [tex]\frac{N \times V_{N}}{V_{C}}[/tex]

It is given that atomic radius is 0.123 nm and density of metal is 7.45 [tex]g/cm^{3}[/tex].

Hence, number of atoms will be calculated as follows.

         No. of atoms = [tex]\frac{density}{\text{atomic radius \times Avogadro's number}}[/tex] = 4

             APF = [tex]\frac{4 \times \frac{4}{3} \pi (0.123 nm)^{3}}{(0.434)^{2}(0.357)}[/tex]        

                     = 1.3905

Thus, we can conclude that atomic packing factor if the unit cell has a  tetragonal symmetry is 1.3905.

ACCESS MORE