Answer:
the intensity will be 4 times that of the earth.
Explanation:
let us assume the following:
intensity of light on earth =J
distance of earth from sun = d
intensity of light on other planet = K
distance of other planet from sun = [tex]\frac{d}{2}[/tex] (from the question, the planet is half as far from the sun as earth)
from the question the intensity is inversely proportional to the square of the distance, hence
J[tex]d^{2}[/tex] = 1 ... equation 1
K[tex](\frac{d}{2}) ^{2}[/tex] = 1 ....equation 2
J[tex]d^{2}[/tex] = K[tex](\frac{d}{2}) ^{2}[/tex]
J[tex]d^{2}[/tex] = K[tex]\frac{d^{2}}{4}[/tex]
J = [tex]\frac{K}{4}[/tex]
K = 4J
intensity of light on other planet (K) = 4 times intensity of light on earth (J)