g The Bohr effect in hemoglobin ... Group of answer choices enhances O2 release in respiring tissues. inhibits O2 release in respiring tissues. has no effect on O2 release in respiring tissues.

Respuesta :

Answer:

enhances O2 release in respiring tissues

Explanation:

Two factors  determine the binding of oxygen with haemoglobin(Hb)  in the lungs;

the high partial pressure of oxygen in the lungs ,  low partial pressure at the respiring tissues

and

the high  partial pressure of carbon dioxide in the blood

Hb binds with oxygen in the lungs and transports this  in the blood to the cells. In the respiring  cells C02 diffuses from the respired cells to the blood plasma.It combines with the plasma to form cabonic acid (H2C03), This reversible  reaction is catalysed by the enzyme carbonic anhydrase.

                         C02 + H20           ⇄        H2C03.

                                           carbonic anhydrase,

the H2C03, breaks down to  hydrogen ion and  hydrogen carbonate ion in the blood .

                             H2C03 ⇄ H+    +       H2C03-

The above reaction produces two effects;

1.The hydrgen ion lowers the blood pH,and increases its acidity. Hb  mops up the hydrogen ions by  combining with  it to form haemoglobinic acid(HHb). Thus acting as buffers to lower the blood pH.

2.Most importantly the high partial pressure of C02 in the blood made Hb to release its oxygen molecules to the blood to reach the tissues(Bohr effect)  while the hydrogen ion  it bonded with  in HHb, combines with hydrogen carbonate ion in the blood , to be transported in the blood to the lungs.

      H + HC03-  ⇄ H2C03 the carbonic acid breaks down to release  C02 in the lungs.

Therefore the high partial pressure of C02  in the blood enabled the release of Oxygen by haemoglobin to the respiring tissues from the blood. This is Borh effect, discovered by Christain Borh in 1904.

A dissociation  curve will show  high bonding of Hb with oxygen at high partial pressure of C02 with Hb, making the curve to move far right of the normal curve.

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