Question

A child is building a tower with colored bricks. She has 21 bricks: 5 yellow, 4 blue, 2 green, and 10 red. She selects a brick at random to stack on the tower. Enter all answers as decimals and round to four places.

Answer 1

Answer:

The probability of picking a Yellow, Blue, green and red brick respectively is 0.2381, 0.1905, 0.0952 and 0.4762.

Step-by-step explanation:

If all bricks have an equal chance to get picked, the probability can be calculated as:

$P(b=x)=\displaystyle\frac{n\ºx_{brick}}{n\ºtotalcases}$

The number of total bricks is 21. Therefoere the probability of picking a Yellow, Blue, green and red brick respectively is:

$P(b=Y)=\displaystyle\frac{n\ºx_y}{n\ºtotalcases}=\frac{5}{21}=0.2381$

$P(b=bl)=\displaystyle\frac{n\ºx_{bl}}{n\ºtotalcases}=\frac{4}{21}=0.1905$

$P(b=g)=\displaystyle\frac{n\ºx_g}{n\ºtotalcases}=\frac{2}{21}=0.0952$

$P(b=R)=\displaystyle\frac{n\ºx_R}{n\ºtotalcases}=\frac{10}{21}=0.4762$