Question

Charge: A piece of plastic has a net charge of +2.00 μC. How many more protons than electrons does this piece of plastic have? (e = 1.60 × 10-19 C)

Answer 1

Answer

given,

net charge = +2.00 μC

we know,

1 coulomb charge =  6.28 x 10¹⁸electrons

1 micro coulomb  charge =  6.28 x 10¹⁸ x 10⁻⁶ electron

                                         = 6.28 x 10¹² electrons

2.00 μC = 2 x 6.28 x 10¹² electrons

              = 1.256 x 10¹³ electrons

since net charge is positive.

The number of protons should be 1.256 x 10¹³ more than electrons.

hence, +2.00 μC have 1.256 x 10¹³ more protons than electrons.

Answer 2

The piece of plastic has  $1.256\times 10^{13} \;\rm protons$  more than  that of electrons.

Given data:

The magnitude of charge on piece of plastic is, $q = +2.00 \;\rm \mu C = +2.00 \times 10^{-6} \;\rm C$.

Since, protons carry positive charge. Then, we know that standard number of proton in 1 Coulomb of charge is,

$1 \;\rm C=6.28 \times 10^{18} \;\rm protons$.

Number of protons in 1 microcoulomb charge is,

$= 6.28 \times 10^{18} \times 10^{-6}\\= 6.28 \times 10^{12} \;\rm protons$

Then for the net charge of q, the number of protons is given as,

$n_{p}=q \times 6.28 \times 10^{12}\\\\n_{p}= 2 \times 6.28 \times 10^{12}\\\\n_{p}= 1.256\times 10^{13} \;\rm protons$

Thus, the piece of plastic has  $1.256\times 10^{13} \;\rm protons$  more protons than electrons.

learn more about the electric charge properties here:

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