Answer:
The units of the constant "0.027" is inchH₂O·inch^(1.22)/fit
Explanation:
The constant has to be consistent with all the other units of this equation:
[tex]\Delta P [InH_2O]=\displaystyle 0.027[x]\frac{L[ft]}{(d[in])^{1.22}}(\frac{v[ft/min]}{v_0[ft/min]})^{1.82}[/tex]
Therefore:
[tex][InH_2O]=\displaystyle [x]\frac{[ft]}{([in])^{1.22}}(\frac{[ft/min]}{[ft/min]})^{1.82} \leftrightarrow [x]=\frac{[InH_2O][in]^{1.22}}{[ft]}[/tex]