Answer:
17 m/s south
Explanation:
[tex]m_1[/tex] = Mass of dog = 10 kg
[tex]m_2[/tex] = Mass of skateboard = 2 kg
v = Combined velocity = 2 m/s
[tex]u_1[/tex] = Velocity of dog = 1 m/s
[tex]u_2[/tex] = Velocity of skateboard
In this system the linear momentum is conserved
[tex](m_1+m_2)v+m_1u_1+m_2u_2=0\\\Rightarrow u_2=-\dfrac{(m_1+m_2)v+m_1u_1}{m_2}\\\Rightarrow u_2=-\dfrac{(10+2)2+10\times 1}{2}\\\Rightarrow u_2=-17\ m/s[/tex]
The velocity of the skateboard will be 17 m/s south as the north is taken as positive