3] Sketch the i(v) characteristic equation of a battery rated at 10 V with an internal resistance of 10 . What is the current drawn from the battery when its terminals are shorted?

Respuesta :

Answer:

1A

Explanation:

For this case we can use the Ohm's law to calculate the current -> v = i*R

Because we have a fix battery voltage and a fix internal resistance -> 10 = i*10 solving for i we get i = 1 Ampere.

To see in detail how this phenomenon works see the pictures of an LTspice simulation of the situation.

Note: All real batteries have a resistance-associated, making a short circuit between the two terminals is not recommended, it can damage the battery and is not safe, note that lower internal resistance increases the current across the terminals.

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