A merry-go-round has a period of 0.64 seconds. Its radius is 1.8 meters. What is its centripetal acceleration?

The centripetal acceleration is 172 m /s^2.
Explanation:
The acceleration that causes an object to move along a circular path, or turn is known as the centripetal acceleration. Centripetal acceleration points radially inward from the object's position and making a right angle with the object's velocity vector.
The centripetal acceleration is given as
Ac = v^2 / r
where Ac represents the centripetal acceleration of an object.
v represents the linear velocity
r represents the radius of rotation.
Given t = 0.64 s, r = 1.8 m.
To find linear velocity, v = (2 * pi * r) / t
= (2 * 3.14 * 1.8) / 0.64
v = 17.6 m / s.
Centripetal acceleration = v^2 / r
= (17.6 * 17.6) / 1.8
= 172 m / s^2.