Answer:
[tex]C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}[/tex]
Step-by-step explanation:
We are given the following in the question:
A storage shed is to be built in the shape of a (closed) box with a square base.
Volume = 150 cubic feet
Let s be the edge of square base and h be the height.
Volume of cuboid =
[tex]l\times b\times h[/tex]
where l is the length, b is the base and h is the height.
Volume of box =
[tex]s^2h = 150\\\\h = \dfrac{150}{s^2}[/tex]
Area of base =
[tex]\text{side}\times \text{side} = s^2[/tex]
Cost of concrete for the base = $4
Cost of base($) = [tex]4s^2[/tex]
Area of roof =
[tex]\text{side}\times \text{side} = s^2[/tex]
Cost of material for the roof = $2
Cost of roof ($) = [tex]2s^2[/tex]
Area of 4 walls =
[tex]4\times (sh)\\=4sh[/tex]
Cost of material for the side = $2.50
Cost of material of side($) =
[tex]2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}[/tex]
Total cost
= Cost of base + Cost of 4 sides + Cost of roof
[tex]C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}[/tex]
is the required cost function.