Answer:
mass of Cu = 26,34615g
Explanation:
The equation for reaction is
Cu + 2 AgNO3 ---> Cu(NO3)2 + 2 Ag
1mol 2mol 1mol 2mol
mass of Ag that reacted = 89.5g
molar mass of Ag =107.86h/mol
number of moles = mass/molar mass
number of moles of Ag = 89.5/107.86
=0.8298moles
from the stoichoimetric relation;
1mol of Cu reacted to produce 2moles of Ag;
hence 0.8298moles of Ag produce would require; 0.8298/2 moles of Cu to react
=0.4149moles of Cu
mass of Cu = moles of Cu * molar mass of Cu
molar mass(Cu) = 63.5g
mass of Cu = 0.4149 * 63.5
mass of Cu = 26,34615g
The mass of copper required to produce 89.5 grams of Ag has been 26.38 grams.
From the given balanced chemical equation, for the production of 2 moles of Ag, 1 mole of copper has been reacted.
The moles of a compound has been given by:
[tex]\rm Moles=\dfrac{Mass}{Molar\;mass}[/tex]
The moles of Ag in 89.5 grams has been:
[tex]\rm Moles\;Ag=\dfrac{89.5}{107.86}\\Moles= 0.83\;mol[/tex]
The moles of Ag in 89.5 grams have been 0.83 mol.
From the balanced equation, moles of copper required to produce 0.83 mol Ag has been:
[tex]\rm 2\;mol\;Ag=1\;mol\;Cu\\ 0.83 mol\;Ag=\dfrac{1}{2}\;\times\; 0.83 \;mol\;Cu\\ 0.83\;mol\;Ag= 0.415\;mol\;Cu[/tex]
The moles of copper required to produce 0.83 mol Ag have been 0.415 mol.
The mass of copper has been given as:
[tex]\rm Mass=Moles\;\times\;Molar\;mass\\Mass=0.415\;\times\;63.546\;g\\Mass=26.38\; mol[/tex]
The mass of copper required to produce 89.5 grams of Ag has been 26.38 grams.
For more information about mass required, refer to the link:
https://brainly.com/question/1706171
