101.4 Litres of Oxygen produced.
Explanation:
2KClO₃→2 KCl + 3O₂
By using the molar mass of KClO₃ we have to find the moles of KClO₃ in the mass of 365 g of sample as,
365 g * 1 mol of KClO₃ / 122.55 g = 2.978 moles of KClO₃
Now we have to find the number of moles of oxygen as
2.978 moles of KClO₃*3 moles O₂ / 2 moles KClO₃= 4.467 moles of O₂
Now using the moles of oxygen, we can find the volume of oxygen produced at STP (standard temperature and pressure).
4.467 moles of O₂ * 22.7 L / 1 mol = 101.4 L of O₂ produced.
