Answer:
[tex]\displaystyle x \approx 0.884[/tex]
General Formulas and Concepts:
Symbols
- e (Euler's Number) ≈ 2.71
Pre-Algebra
Algebra I
- Exponential Rule [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]
Algebra II
- Natural Logs ln and Euler's number e
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle ln(x) = -0.123[/tex]
Step 2: Solve for x
- [Equality Property] e both sides: [tex]\displaystyle e^\bigg{ln(x)} = e^\bigg{-0.123}[/tex]
- Simplify: [tex]\displaystyle x = \frac{1}{e^\bigg{0.123}}[/tex]
- Evaluate: [tex]\displaystyle x = 0.884264[/tex]
- Round: [tex]\displaystyle x \approx 0.884[/tex]