Respuesta :

Answer:

Acceleration of the car will be [tex]a=8m/sec^2[/tex]

Explanation:

We have given that car starts from rest so initial velocity of the car u = 0 m/sec

And car traveled 400 m in 10 sec

So distance traveled by car s = 400 m

Time taken to compete this distance t = 10 sec

We have to find the acceleration of the car

From second equation of motion we know that [tex]s=ut+\frac{1}{2}at^2[/tex]

So [tex]400=0\times 10+\frac{1}{2}\times a\times 10^2[/tex]

[tex]a=8m/sec^2[/tex]

So acceleration of the car will be [tex]a=8m/sec^2[/tex]

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