Question

A bullet in a gun is accelerated from rest from the firing chamber to the end of the barrel at an average rate of 6.2 × 105 m/s2 for 8.05 × 10-4 s.What is its muzzle velocity (that is, its final velocity)?

Answer 1

To solve this problem we will start from the concept of the linear motion kinematic equations. For this purpose we will consider the acceleration as the change of the speed in an instant of time, that is to say

$a = \frac{v-u}{t}$

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = time

Rearranging to find the terminal velocity,

The muzzle velocity of a bullet is the velocity with which the bullet leaves contact with the barrel of the gun.

Replacing we have,

$v = 0 +(6.2*10^5)(8.05*10^{-4})$

$v = 499.1m/s$

Therefore the muzzle velocity of the bullet is 499.1 m/s