To help answer this question, Deigo wrote the division equation 3/4 divided by 2/5. Explain why this equation does not represent the situation. This is the situation After raining for 3/4 of an hour, a rain gauge is 2/5 filled. If it continues to rain at that rate at that rate for 15 more minutes, what fraction of the rain will be filled.

Respuesta :

Answer:

The fraction of the rain filled in the gauge will be =  [tex]\frac{8}{15}[/tex]

Diego wrote the division equation incorrectly.

It must be given as [tex]\frac{2}{5}[/tex] divided by [tex]\frac{3}{4}[/tex] .

Step-by-step explanation:

Given:

After [tex]\frac{3}{4}[/tex] of an hour of rain the rain gauge is [tex]\frac{2}{5}[/tex] filed.

To find the fraction of the rain that will be filled in the gauge if it continues to rain at the same rate for 15 more minutes.

Solution:

15 minutes in hours will be = [tex]15\ min \times \frac{1\ hour}{60\ min}[/tex] = [tex]\frac{1}{4}[/tex] of an hour.

Given that it has rained for [tex]\frac{3}{4}[/tex] of an hour, and it continues to rain for  [tex]\frac{1}{4}[/tex] of an hour more.

Thus, total time of rain will be = [tex]\frac{3}{4}+\frac{1}{4}=\frac{4}{4}=1\ hour[/tex]

Using unitary method to find the fraction of rain filled in the gauge after 1 hour of rain.

If in  [tex]\frac{3}{4}[/tex] of an hour of rain the rain gauge is [tex]\frac{2}{5}[/tex] filed.

Thus, in 1 hour of rain the gauge will be filled by = [tex]\frac{2}{5}\div \frac{3}{4}[/tex]

To divide fractions, we take reciprocal of the divisor and replace division by multiplication.

⇒ [tex]\frac{2}{5}\times\frac{4}{3}[/tex]

⇒ [tex]\frac{8}{15}[/tex]

Thus, the fraction of the rain filled in the gauge will be =  [tex]\frac{8}{15}[/tex]

Diego wrote the division equation incorrectly.

It must be given as [tex]\frac{2}{5}[/tex] divided by [tex]\frac{3}{4}[/tex] .

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