Respuesta :
Answer:
The fraction of the rain filled in the gauge will be = [tex]\frac{8}{15}[/tex]
Diego wrote the division equation incorrectly.
It must be given as [tex]\frac{2}{5}[/tex] divided by [tex]\frac{3}{4}[/tex] .
Step-by-step explanation:
Given:
After [tex]\frac{3}{4}[/tex] of an hour of rain the rain gauge is [tex]\frac{2}{5}[/tex] filed.
To find the fraction of the rain that will be filled in the gauge if it continues to rain at the same rate for 15 more minutes.
Solution:
15 minutes in hours will be = [tex]15\ min \times \frac{1\ hour}{60\ min}[/tex] = [tex]\frac{1}{4}[/tex] of an hour.
Given that it has rained for [tex]\frac{3}{4}[/tex] of an hour, and it continues to rain for [tex]\frac{1}{4}[/tex] of an hour more.
Thus, total time of rain will be = [tex]\frac{3}{4}+\frac{1}{4}=\frac{4}{4}=1\ hour[/tex]
Using unitary method to find the fraction of rain filled in the gauge after 1 hour of rain.
If in [tex]\frac{3}{4}[/tex] of an hour of rain the rain gauge is [tex]\frac{2}{5}[/tex] filed.
Thus, in 1 hour of rain the gauge will be filled by = [tex]\frac{2}{5}\div \frac{3}{4}[/tex]
To divide fractions, we take reciprocal of the divisor and replace division by multiplication.
⇒ [tex]\frac{2}{5}\times\frac{4}{3}[/tex]
⇒ [tex]\frac{8}{15}[/tex]
Thus, the fraction of the rain filled in the gauge will be = [tex]\frac{8}{15}[/tex]
Diego wrote the division equation incorrectly.
It must be given as [tex]\frac{2}{5}[/tex] divided by [tex]\frac{3}{4}[/tex] .
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