Question

b-2a^2/b^2-a/b^2-a where a=-3 and b=-1 answer should be in a improper fraction, if appropriate.

Answer 1

Answer:

$\Rightarrow -\dfrac{73}{4}$

Step-by-step explanation:

The given expression, $\dfrac{b-2a^2}{b^2}-\dfrac{a}{b^2-a}$

where, a = -3 and b = -1

Put the value of a and b into expression

$\Rightarrow \dfrac{(-1)-2(-3)^2}{(-1)^2}-\dfrac{(-3)}{(-1)^2-(-3)}$

Simplify each parentheses

$\Rightarrow \dfrac{-1-18}{1}+\dfrac{3}{1+3}$

$\Rightarrow -19+\dfrac{3}{4}$

Now make same denominator

$\Rightarrow -\dfrac{76}{4}+\dfrac{3}{4}$

$\Rightarrow \dfrac{-76+3}{4}$

$\Rightarrow -\dfrac{73}{4}$

This is improper fraction because numerator is greater than denominator.