Question

How long does it take to send a 14 MiB file from Host A to Host B over a circuit-switched network, assuming:
Total link transmission rate = 31.1 Gbps.
Network is TDM, with 11 permitted users, each with an equal time slot size.
A link connection requires a setup time of 51.7 ms.

Answer 1

Answer:

t = 93.2 msec.

Explanation:

If the network is TDM, this means that the total bandwidth is divided between the different users, giving each user a dedicated time slot to transmit data.

So, the transmission rate dedicated to one single user, can be obtained as follows:

$R = \frac{31.1} {11} Gbs = 2.83 Gbs$

The pure transmission time, will be the quotient between the file size (in bits) over the dedicated bandwidth for a single user.

If the file size is 14 MiB, we know that 1 MiB =  2²⁰ bytes = 1,048,576 bytes.

⇒ $14 MiB = 1,048,576 Bytes * 8 (bits/byte) = 117,440,512 bits$

⇒ $t = \frac{117,440,512 bits}{2.83 Gbs} = 0.0415 sec = 41. 5 msec$

The total transmission time, will be the sum of the pure transmission time, plus the setup time:

$T = 51.7 msec + 41. 5 msec = 93.2 msec$