Question

How much work (in J) is required to expand the volume of a pump from 0.0 L to 2.7 L against an external pressure of 1.0 atm?

Answer 1

Answer:

-2.79 x 10²J

Explanation:

using the pressure volume work formula which states that

work = -PΔV

           = -(1.0 atm) (2.7-0.0)L = -2.7L . atm

Convert litre.atmosphere to Joules.

1 L . atm = 101.325 joules

-2.75 L .atm = -2.75 x 101.325 = -278.64375 =

Work = -2.79 x 10²J

Answer 2

The work required to expand the volume of the pump is -273.58 J

Given the data in the question;

• Initial volume; $v_1 = 0$

• Final volume; $v_2 = 2.7L = 0.0027m^3$

• Pressure; $P = 1.0atm = 101325pa$

Work done; $W = \ ?$

From the first law of thermodynamic:

$W = -P\delta v$

Where W is work done, P is pressure and $\delta v$ is change in volume.

We substitute in our values

$W = -[ 101325Pa\ *\ [ 0.0027m^3 - 0 ] ]\\\\W = -[ 101325Pa\ *\ 0.0027m^3 ]\\\\W = - 273.58Pa.m^3\\\\W = - 273.58J$

Therefore, the work required to expand the volume of the pump is -273.58 J

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