Question

A student calculated the number of moles of carbon dioxide present in a 100.0 g
sample of a gaseous mixture. If the student determined that there are 0.30 moles of
carbon dioxide present in the sample, what is the percent composition of carbon
dioxide in the sample?

Answer 1

Answer: 13.2%

Explanation:

Mass of the sample = 100g

MM of CO2 =12+ (16 x 2) = 44g/mol

Number of mole of CO2 present in the sample = 0.3

Mass conc. Of CO2 present = 0.3 x 44 = 13.2g

Percentage of CO2 in the sample = (13.2 / 100) x 100 = 13.2%

Answer 2

The percent composition of carbon dioxide in the sample is 13.2%

• The calculation is as follows:

Mass of the sample = 100g

MM of CO2 $=12+ (16 \times 2)$= 44g/mol

Number of mole of CO2 present in the sample = 0.3

And,

Mass conc. Of CO2 present =$0.3 \times 44$= 13.2g

So,

Percentage of CO2 in the sample = $(13.2 \div 100) \times 100$ = 13.2%

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