Answer:
4.4857 seconds
No
Explanation:
L = Length of the pendulum = 5 m
g = Acceleration due to gravity = 9.81 m/s²
Time period is given by
[tex]T=2\pi\sqrt{\dfrac{L}{g}}\\\Rightarrow T=2\pi\sqrt{\dfrac{5}{9.81}}\\\Rightarrow T=4.4857\ s[/tex]
The optimum time interval in between the pushes is 4.4857 seconds
It can be seen that the mass of the child is not used in the formula and hence changing the mass would not result in a different time period.
The length of the pendulum and the acceleration of gravity of the planet determines the time period.