Answer:
[tex]=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}[/tex]
Step-by-step explanation:
Given expression as:
[tex]=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }[/tex]
We need to simplify the given expression.
Solution:
We have:
[tex]=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }[/tex]
Rewrite the expression as:
[tex]=\frac{\sqrt{7}}{3\sqrt{2}} - \frac{\sqrt{7}}{\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]
[tex]\frac{\sqrt{7}}{\sqrt{2} }[/tex] is a common factor to the first two terms.
Using distributive property we can factor out [tex]\frac{\sqrt{7}}{\sqrt{2} }[/tex] from the first two terms.
[tex]=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1}{3} -1) +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]
[tex]=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1-3}{3}) +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]
[tex]=\frac{\sqrt{7}}{\sqrt{2}}(\frac{-2}{3}) +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]
[tex]=-\frac{2\sqrt{7}}{3\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]
[tex]\sqrt{2}[/tex] is common factor, so we can factor [tex]\sqrt{2}[/tex] from the above expression.
[tex]=\frac{1}{\sqrt{2} }( -\frac{2\sqrt{7}}{3} +\frac{\sqrt{5}}{2})[/tex]
[tex]=\frac{1}{\sqrt{2} }( \frac{-2\times 2\sqrt{7}+3\times \sqrt{5}}{6})[/tex]
[tex]=\frac{1}{\sqrt{2} }( \frac{-4\sqrt{7}+3\sqrt{5}}{6})[/tex]
[tex]=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}[/tex]
Therefore, we get simplified answer as.
[tex]=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}[/tex]