Respuesta :

Answer:

[tex]=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}[/tex]

Step-by-step explanation:

Given expression as:

[tex]=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }[/tex]

We need to simplify the given expression.

Solution:

We have:

[tex]=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }[/tex]

Rewrite the expression as:

[tex]=\frac{\sqrt{7}}{3\sqrt{2}} - \frac{\sqrt{7}}{\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]

[tex]\frac{\sqrt{7}}{\sqrt{2} }[/tex] is a common factor to the first two terms.

Using distributive property we can factor out [tex]\frac{\sqrt{7}}{\sqrt{2} }[/tex] from the first two terms.

[tex]=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1}{3} -1) +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]

[tex]=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1-3}{3}) +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]

[tex]=\frac{\sqrt{7}}{\sqrt{2}}(\frac{-2}{3}) +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]

[tex]=-\frac{2\sqrt{7}}{3\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}[/tex]

[tex]\sqrt{2}[/tex] is common factor, so we can factor [tex]\sqrt{2}[/tex] from the above expression.

[tex]=\frac{1}{\sqrt{2} }( -\frac{2\sqrt{7}}{3} +\frac{\sqrt{5}}{2})[/tex]

[tex]=\frac{1}{\sqrt{2} }( \frac{-2\times 2\sqrt{7}+3\times \sqrt{5}}{6})[/tex]

[tex]=\frac{1}{\sqrt{2} }( \frac{-4\sqrt{7}+3\sqrt{5}}{6})[/tex]

[tex]=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}[/tex]

Therefore, we get simplified answer as.

[tex]=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}[/tex]

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