Stacy is selling tickets for the school play. She has a total of 200 seats available, and there will be two types of tickets offered, child and adult tickets. If she sold each child ticket for $6 , each adult ticket for $10 , and made a total of $1704, how many of each ticket did she sell?

She has a total of 200 seats available, and there will be two types of tickets offered, child and adult tickets
She sold each child ticket for $6 , each adult ticket for $10 , and made a total of $1704

We need to find how many of each ticket she sold

Assume that x is the number of child tickets and y is the number of the adult tickets

∵ She has a total of 200 seats available

∵ She sold x child tickets

∵ She sold y adult tickets

- Add x and y, then equate the sum by 200

∴ x + y = 200 ⇒ (1)

∵ She sold each child ticket for $6

∵ She sold each adult ticket for $10

∵ She made a total of $1704

- Multiply x by 6 and y by 10, then add the products and

equate them by 1704

∴ 6x + 10y = 1704 ⇒ (2)

Now we have a system of equation to solve it

Multiply equation (1) by -10 to eliminate y

∵ -10x - 10y = -2000 ⇒ (3)

- Add equations (2) and (3) to find x

∴ -4x = -296

- Divide both sides by -4

∴ x = 74

- Substitute the value of x in equation (1) to find y

∵ 74 + y = 200

- Subtract 74 from both sides

∴ y = 126

She sold 74 child tickets and 126 adult tickets

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly